`(1/2)log9+2log3-log6+log2-2`

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Answer:
log 9/100
Step-by-step explanation:
1/2 log 9 + 2 log 3 - log 6 + log 2 - 2
= log 3^(2*1/2) + log 3^2 - log 6 + log 2 - 1 - 1
= log 3 + log 9 - log 6 + log 2 - log 10 - log 10 [ Since 1 = log 10 because log 10 is equal to 10^x=10 and x further equals to 1]
= log { ( 3 * 9 * 2) / (6 * 10 * 10) } [ Using logarithms product law in which log x + log y = log x * y and also using division low in which log x - log y = log x / y]
= log { 54 / 600 }
= log (9 / 100)

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`(1/2)log9+2log3-log6+log2-2`

`(1/2)log9+2log3-log6+log2-2`

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