If `f(x)=cos(lnx)` then `f(x)f(y)-1/2(f(x/y)+f(xy))` has the value

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If `f(x)=cos (logx)`, 0:04:03

If `f(x)=cos (logx)`, then `f(x)f(y)-1/2[f(x/y)+f(xy)]=`

If `f(x)=cos(lnx)` then 0:03:04

If `f(x)=cos(lnx)` then `f(x)f(y)-1/2(f(x/y)+f(xy))` has the value

If `f(x)=cos(logx)`, then 0:03:35

If `f(x)=cos(logx)`, then `f(x)f(y)-1/2[f(x/y)+f(xy)]`=

If f(x)=cos (log 0:03:05

If f(x)=cos (log x), then f(x) · f(y)-1/2[f(x/y)+f(x y)] has the value (1983,1 M) (a) -1 (b) 1/2 ......

If `f(x) = 0:04:35

If `f(x) = cos (log _(e) x),` then `f (x) f(y) -1/2 [f(xy) +f((x)/(y))]` has the value-

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