The PA = LU factorization with row exchanges

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Honestly there was a particular segment i was looking for for days and you just absolutely breezed it well . Thank you very very much
. God bless you

kevinebedi
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Hi, i am an Italian student at the first year of computer science engineering.You did in 5 minutes what my teacher has done in more than 1 hour(teaching it very bad), i want to say you thanks.

bella-rprw
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To generalize what she said:

Use Gaussian Elimination to find U (the diagonal values do not have to be 1).

PA is the matrix found after row swapping (but before row subtraction) during the Gaussian Elimination. P is the diagonal matrix after row swapping.

The L matrix has 1s along the diagonal, and the other lower triangular values are the values at their location with the value they had when eliminated to zero during Gaussian elimination divided by the pivot value of that column (at that same time).

Gaussian elimination eliminates the top, to the bottom, then to the right

jaredtweed
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Thank You so much, you explained it really well.

deepanshuchaudhary
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good quality of sound and image! perfect information! But i scipped the first minute.

jaromatt
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The explanation really helps!!! Thanks a lot.

granthuang
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Wow perfectly explained. Thank you for such a clear explanation

jonasasare
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Izy Pls, which software did you use to write the presentation? Thanks

akeemolowolayemo
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hello, I think there is a problem with the matrix L. it should be 1 0 0 / 0 1 0 / -2 -3 1. Is it true?

halilibrahimkocak
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malum aile herkesin aklında geziniyor soruyu çözerken

murathanbakr