Mechanical Engineering Thermodynamics - Lec 32, pt 1 of 3: Combustion - Excess Air

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  1. Ron Hugo
  2. Mechanical Engineering (Professional Field)
  3. Combustion
  4. Thermodynamics (Field Of Study)
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Комментарии
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I was here for Heat Transfer but I'm back for Thermo! 😂 You are such a good lecturer!

AK-gtzy
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No - it should be multiplied by 3.  0% excess air is the correct amount of air based on the stoichiometric balance, and thus it is 1*a_th.  For 100% excess air it is 100% more air than you need, and thus it is 2*a_th.  For 200% excess air it would be 3*a_th.

ronhugo
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a should be 4.5 6:55 ı dont know you still checking youtube but you are great sir

hakan
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Thanks a lot. Why didn't you put the stoichiometric equation from the beginning if you knew that you have excess air? I mean you multiply the air by 3 and add the Oxygen to the right.

SultanAlawad
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thx, greetings from Monterrey, México

cclh
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Thank you so much for all your videos. I really appreciate it and rely on it, again thank you.

harjinderooney
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why 200 % excess air deals with 3*theo air?

dreamer
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100% theoretical air = 0% excess air = a_th
200% theoretical air = 100% excess air = 2 a_th
300% theoretical air = 200% excess air = 3 a_th

Am I right?

crowdoesfly
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for 200% excess air should a-theoretical be multiplied by 2?

fredlyraphael
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Sir how if the problem said "the amount of O2 provided in the form of air (21% O2 and 79% N2) should be twice of the amount needed from the reaction" does it mean we have to multiply the a_th by 2 or the excess air is 200% ?

muhammaddafi
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Propane gas is allowed to react with 80% theoretical air. Determine the
theoretical equation for the reaction. what to do in this case?

bickromsahamithu
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Hi could you please make video about combustion for Foundamental test exam please help

Moh-iisf