45-Fourier transform of a Gaussian

The Gaussian function has an important role in PDEs and so we go over direct computation of the this function

[chandus]

for the last two hours i was trying to out different ways to integrate the Gaussian. five min into your video and i was like so you CANT integrate the Gaussian simply. Thanks a lot!!

[andrewmartinburger]

This was a really thorough proof. Thank you for your excellent explanation of this.

[victorreis]

Thank You Master, great lecture, greetings from Physics Engineering course of UFSCar

[vitorlopes]

in the begining of the video, the expression you wrote for the fourier transform is actually the inverse fourier transform.

[ura]

Cool solution, I learned how to solve the Gaussian pulse using a different method.

[ura]

I highly recommend " partial differential equations for scientists and engineers " by Farlow.

[kironsk]

vlw velho único video da internet que resolve isso

[JohnVKaravitis]

Area under a gaussian with stan dev (sigma) is c and leading coefficient in front of exp(), "a", is a*c*sqrt(2*pi). When you are given a Gaussian, the leading coefficient of the function is (sigma * sqrt (2*pi))^-1, which thus forces the area under the Gaussian to be = 1. So here, at 17:06, I = sqrt(2*pi), not sqrt(pi).

[bashirudeenkatorefadeel]

Why was the "i" eliminated when finding C

[thereallpb]

Hopefully i will have a fast reply: The Fourier Transform of e^ [-alfa*(x^2)] = integral (from -inf to +inf) of e^ [-alfa*(x^2)] * e^ -iwx * dx, isn't it?

[cesaralvaradogarcia]

en quie puto idioma escribes''''???? jajaja
gracias