Calculate Perimeter of Trapezoid | Area of Trapezoid is 486 | Trapezium | Important skills explained

preview_player
Показать описание

Today I will teach you tips and tricks to solve the given olympiad math question in a simple and easy way. Learn how to prepare for Math Olympiad fast!

Need help with solving this Math Olympiad Question? You're in the right place!

I have over 20 years of experience teaching Mathematics at American schools, colleges, and universities. Learn more about me at

Calculate Perimeter of Trapezoid | Area of Trapezoid is 486 | Trapezium | Important skills explained

Olympiad Mathematical Question! | Learn Tips how to solve Olympiad Question without hassle and anxiety!

#Trapezoid #Trapezium #GeometryMath #Perimeter #PerimeterOfTrapezoid
#MathOlympiad #Quadrilateral #AreaOfTrapezoid #Square
#OlympiadMathematicalQuestion #HowToSolveOlympiadQuestion #MathOlympiadQuestion #MathOlympiadQuestions #OlympiadQuestion #Olympiad #AlgebraReview #Algebra #Mathematics #Math #Maths #MathOlympiad #HarvardAdmissionQuestion
#MathOlympiadPreparation #LearntipstosolveOlympiadMathQuestionfast #OlympiadMathematicsCompetition #MathOlympics #CollegeEntranceExam
#blackpenredpen #MathOlympiadTraining #Olympiad Question #GeometrySkills #GeometryFormulas #AreaOfTriangles #Rectangle #PythagoreanTheorem
#MathematicalOlympiad #OlympiadMathematics #CompetitiveExams #competitiveexams #AreaOfRectangle #AreaOfTriangles #RightTriangle

How to solve Olympiad Mathematical Question
How to prepare for Math Olympiad
How to Solve Olympiad Question
How to Solve international math olympiad questions
international math olympiad questions and solutions
international math olympiad questions and answers
olympiad mathematics competition
blackpenredpen
math olympics
olympiad exam
olympiad exam sample papers
math olympiad sample questions
math olympiada
British Math Olympiad
olympics math
olympics mathematics
olympics math activities
olympics math competition
Math Olympiad Training
How to win the International Math Olympiad | Po-Shen Loh and Lex Fridman
Po-Shen Loh and Lex Fridman
Number Theory
There is a ridiculously easy way to solve this Olympiad qualifier problem
This U.S. Olympiad Coach Has a Unique Approach to Math
The Map of Mathematics
mathcounts
math at work
Pre Math
Olympiad Mathematics
Two Methods to Solve System of Exponential of Equations
Olympiad Question
Find Area of the Shaded Triangle in a Rectangle
Geometry
Geometry math
Geometry skills
Right triangles
imo
Competitive Exams
Competitive Exam
Quadrilateral
Rectangle
College Entrance Exam
College Entrance Question
Triangle
Square
Trapezoid
Trapezium
Pythagorean Theorem
Perimeter
Area
Right triangle

Subscribe Now as the ultimate shots of Math doses are on their way to fill your minds with the knowledge and wisdom once again.
Рекомендации по теме
Комментарии
Автор

Good problem solving, sir. U are awesome. Love from KZ🇰🇿

ix_azeka
Автор

Si llamamos side "S" a los lados iguales:
Área=486cm²
Area= S²+S²/2=3/2 S²
S²=486 x 2/3
S= 18 cm

Perímetro = 4 S + S/cos45°
Perímetro= 97, 46 cm. √

marioalb
Автор

97.456
From the edge of the 45-degree line, draw a perpendicular line to the top of the trapezoid.
This line will form an isosceles triangle (45-45-90) and a square since the lines facing
the two 45-degree angles are EQUAL.
Let the sides of the trapezoid = x and y, with y, the longest side
Then the area of the trapezoid is 486 = (( y + x) h)/2
Since x = side of the square and since the triangle to the left is an isosceles, then y=2x
and h= x
hence 486= [(2x + x )x]/2
972= 3x^2
324 =x^2
18 = x
The sides of the trapezoid (excluding the hypotenuse) are : 18, 18, 36 = 72
the hypotenuse can be found by the square root of ( 18^2 + 18^2)
or the square root of 648 =25.4558
The perimeter = 72 + 25.4558 = 97.4558 round to 97.456

devondevon
Автор

Thank you for video. Area of trapezoid can be seen as 1.5 of square ABCE, therefore 1.5 a^2 = 486, then a=18, CD = (sq.root 2)(18), perimeter = (4)(18) + (18)(sq.root 2) =(18)(4 + sq.root 2) = (18) (5.414) = 97.46

normanc
Автор

Happy to say for the first time solved this in a couple minutes by just looking at the thumbnail. Love your geometry quizzes!

moda
Автор

Such an excellent teacher. I am a doctor who learnt this, four decades ago. I still enjoy mathematics and found this channel to be the best. I wish I had him as a teacher and would not have been a doctor. Please keep up the great work, you are a great teacher and inspiration.
Please could you do some program on Vedic mathematics, also if possible categorising all the teaching according to the different branches of mathematics and their severity.🙏🏽🙏🏽🙏🏽

bangaloresatish
Автор

Did the same steps as you did. I paused and tried, got it. Nice problem, thanks for the ideas and time you share. God bless.

jonathanjose
Автор

Good stuff, thank you. I started off trying two isosceles right triangles. It might have been possible that way, but then I realised the square + right isosceles would be easier. I got 72 + 18*sqrt(2). I got rid of the fraction by doubling both sides for 3a^2=972. I ignored Pythagora because the diagonal of a square is sroot2.
Although I use more shortcuts these days, I have learned many of them from you.

MrPaulc
Автор

√ ( Area ÷ 1.5 ) = a
Perimeter = 4a + a √2
√ ( 486 ÷ 1.5 ) = 18
4 * 18 + 18 √2 = 97.45584

mohanramachandran
Автор

We learn a lot because of your question sir

Ankitsingh-yjm
Автор

Nice simple problem, almost mental arithmetic, a great example to try to approximate in your head because it gives it a reasonable brain workout .. thanks very much 👍🏻

theoyanto
Автор

Thanks for uploading. Working on these problems is very satisfying. I try to do them without aid of a calculator too which usually means leaving answers as exact values.

muttleycrew
Автор

Excelente profesor felicidades por el dominio que tiene usted del teorema de Pitágoras y gracias.

bramont
Автор

486x2/3=324, sqrt(324)=18 is the side of the square, thus the perimeter is 18x4+18 root(2)=97.456 approximately, done 😊.g

misterenter-izrz
Автор

Total Area = 486 cm²

Taking 1 of the 3 equals
internal right triangles,

Area triangle= 486 / 3 = 162 cm²
Area triangle = b.h /2 = s²/2=162
s²=2 x 162
s = 18m

Perimeter = 18x4 + 18/cos45°
Perimeter = 97, 46 cm ( Solved √ )

marioalb
Автор

The object can be considered as Three 45° isosceles triangles,

The square component is 2/3 of the total area,

so the side length can be calculated by

Sqrt(486 * 2/3) = 18

As the remaining component is a 45° isosceles triangle we know the length of the hypotenuse is Sqrt(2) times the side length

Sqrt(2) * 18 = 25.45582



25.46 + (18 *4) = 97.46 cm

mahatmapodge
Автор

Area of square = a^2.
Area of triangle = 0.5 (a^2)
a^2 + 0.5 (a^2) = 486.
1.5 (a^2) =486.
a^2 = 486/1.5.
a^2 = 324.
a =18.
Perimeter = 4a + (a x sqrt.2).
72 + (18 x 1.4142)
72 + 25.46.
97.46.

georgebliss
Автор

i got it 72+sqrt(648)
approx.
97.5cm

prithvisinghpanwar
Автор

AB=a → a²=486x2/3 → a=18 → DC=a√2 → Perímetro ABCD =4a + a√2 =a(4+√2) =18(4+√2) =97.4558
Gracias y saludos cordiales.

santiagoarosam
Автор

A long way round a simple solution. By inspection, the tapezoid is made up of three equal sized triangles of area = 162. Two of these form a square therefore a = sqrt 162 x 2 = 18. Therefore circum is 4 x 18 + 18 x sqrt 2.

johnspathonis