Cable subjected to Distributed Load Example 3

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Cable subjected to Distributed load with non symmetric distribution of the geometry
Calculate the tension at the supports
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you’re better than my static professor

esclipsekr
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Sir i have an one important question and it is very doubtful for me. This question is when you determine the tension of B, y then why you calculate sum of fy in whole free body? please answer this question quickly if it is possible for you.

NiazMdRafi
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Sir why you take left side distance x and y in F. horizontal

ZainKhan-cysp
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Thank you so much sir
I bow down to you🙏

manishatiwari
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Thank you so much sir, you help a lot 🥺

ghelen
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Sir, as you said Fh will be same on both side but i calculuted Fh using right side sag and distance there was lil difference your Fh is 3790 and when i calculated using right side my Fh was 3786. I know its not much difference but its not same. Is this difference negligible.
BTW THANKS for video

maskman
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I saw on other notes that the formula for Fh = wL²/8h instead of wL²/2h ?

berkexan
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Hello, this video helped a lot.

Which text book is this from?

alysonmohan
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is the formula same on SI system? say.. N/m..?

petergeorgeednalaga
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How do we find the maximum tension of the cable and also the minimum?

cjayson
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hi, at 6:17 you wrote x=25÷(1.08165) but I think that it must be x=25÷(1.8165)

高佳翰
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This question came in my paper . I just solved it . Online examination . Thanku so much . This question contain 20 marks . So its for sure . Oh yeah .

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