Areas Related to Circles 02 | Area of Combination of Plane Figures | Class 10 | NCERT | Udaan

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•Scheduled Syllabus For Udaan ( Class 10 ) released describing which topics will be taught for how many days.

•Duration :- 4 months (Dec 2020 - March 2021)

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4) Scheduled Syllabus released describing :-
which topics will be taught for how many days.
Available at PhysicsWallah App

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OUR SOCIAL MEDIA PROFILES :

[anshikakushwaha]

First question
Area of shaded region=216/7

[computerscience]

Sir question No 2 .ka mainay directly nikaal diya, jo aapnay bola tha nahi soch payoy gay .All credit to your teaching .Sanyam sir.

[dadrar]

The area of shaded region at 50:04 is
3255.21cm²

[CUTIEPIE-hfrm]

At 58:16 we can use formula 4(side) ^2/7 it would be very easy❤❤❤🎉🎉

[shrishtisahu]

57:43 Sir we can also this question by another way also....By subtracting the area of triangle from a quadrant for only one quadrant then multiply it by 2...We also get the same answer that is 36.57🙂😊

[georgesheikh]

5:21 sir i have done this problem by just seeing the question..

[priyansurout]

I don't know why but at this movement 1:09:50 I fell so happy

[RajeshPandey-pwvb]

Offcourse macha to Diya sir ✍️🔥🔥🔥😁😄😃😀 ye sir ka line hai bhaiyo aur bahno

[shortsyb]

Sir In my maths exam, I got 78 out of 80 because sir but after taking interest in maths my SST marks fall down, I got 56 out 80 in SST😭. Please suggest any tip sir.🙏

[omrajtambat]

29:50 we were able to use D= root (W^2 + d= diagonal w= width l= finding diagonal, we will just make it half it will be radius

[dhruv]

216/7 cm^2 or 30.86 cm^2 [Approx] 1st question

[jagritigupta]

5:46
Area of shaded region = 216/7 cm^2
32:36
Area of shaded region in quadrant is 14.910 (approx) cm^2
34:38
But, sir diagonal of a square are equal so can we not say that side 14 cm is = diagonal means radius = 14 cm?

[mathematicssurgeon-purusho]

*Physics Wallah Sir, Can I get a chance to teach at your platform?* 🔥🔥🔥

[DarkDevil-cizs]

5:46
Area of shaded portion =216/7 cm²

32:32
Area of shaded portion= 14.910 cm² (approx)

[velocxty]

ABSOLUTELY IMPECCABLE session as always!😃👍💪⚡️

[ujjawalmishra]

06:27 It can also be done by :- Area of 4 semicircles - Area of square

[shreyashadhyan]

I'm a student of of Udaan Reloaded, , since this chapter is coming in exam I am watching, hope this will also be completed in our batch soon🙂

[ayushikumari]

54:26 area of abcd - area of abc quadrant=area of adc.
Area of adc quadrant - area of adc = area of desgin

[mindbusters]

Sir can we find the height of the ∆OBC by the centroid formula as O is the centroid of∆ABC and we know that centroid of a ∆ divides its median in the ratio 2:1 😉

[dadrar]

At 1:02:01
The length of track is 449.14m.