Finding the pairs of positive integers m,n satisfying (1/m)+(4/n)=1/12.

This video is about finding the pairs of positive integers m,n which satisfy (1/m)+(4/n)=1/12;and this is CAT-2007 problem.Writing this equation as 1/m=(1/12)-(4/n),which implies 1/m={(n-48)/(12n)}.So,m={(12n)/(n-48)}.Now,its given that m,n are positive integers ,where n is an odd integer less than 60.Therefore n can be 1,3,5,7,......,59.Remember that for the positive integral values of m,12n must be divisible by (n-48);but for the positive values of m, n can only be 49,51,53,55,57,59 ;because if we take the values of n less than 49 ,the values of m corresponding to the values of n will become negative.Now,with the help of trial and error method,we will substitute the values of n in 12n/(n-48) one by one to find the positive integral values of m corresponding to the values of n.
Subscribe: