Statics: Lesson 31 - System Equilibrium, 2D Reactions at the Supports

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Me at 1:07 AM studying for my statics midterm in less then 12 hours. Engineering is hard but keep going guys. You got this!!!

garrettbarringer

As someone already mentioned, T_BC, x = (4/5)T_BC and T_BC, y = (3/5)T_BC.
Which gives,
Ax = (4/5)(15.71) = 12.57 kN
and
Ay = (3/5)(15.71)+2 = 11.426 kN.

zunaidhassan

Great Explanation Professor Hanson. I am also wondering the same for T(BC) components as other said. 4/5 * T(BC) for Horizontal and 3/5 * T(BC) for Vertical. Very best explanation for 2 force member sir.

RK-txxb

"One hop this time", lmao. You know that Dr.Hanson gets DOWN at weddings.

Feignlander

Professor Hanson, thank you for a great explanation of System Equilibrium and 2D Reactions at the Supports. The Free Body Diagrams are excellent.

georgesadler

Shouldn't the horizontal force be 4/5 TBC and the vertical force 3/5 TBC?

ventjemazzel

I got Ax=12.57kN going right and Ay=11.42kN going up for the component forces at A.

Apollo-tmrt

Really good explanation. Looking forward to learn more from you!

jennymoon

Hey Dr. Hanson, been watching all your great videos this summer! Hoped to let you know that you've got a small mistake (3/5Tbc and 4/5Tbc reversed)

jonathanfu

At 10:52 he says that it is clockwise but I got CCW. He still put positive so it should be fine. If the palm is facing point A and the fingers the direction of the force, then it would wrap upwards indicating a ccw direction.

sabahalshawk

I got 12560 = Ax = 4/5 BC and Ay = 11420 = 3/5 BC + 2000

ViktoriaReads

@14:46 Bless you Doctor Handsome... I mean Hanson

Peytdog

The only thing i noticed, why did u add the 2 in Ay? It's negative right?

theapocalypse

hello hopeful for some responses. I am confused about the 3 and 4. I mean how did you end up with those numbers? Also, will 150 and 200 be ok to use and not 3 and 4 ?

adrianmonteclaro