Ex-10.2 Q-9,10 | Chapter 10 | NCERT | Class 10th Math |

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Ex-10.2 Q-9,10 Chapter 10 NCERT Class 10th CBSE/ICSE/HBSE All State Board Easy Method By Deepak Antil Sir

Ex-10.2 Q-9,10 | Chapter 10 | NCERT | Class 10th Math |

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[BlackPanther-nunt]

Question 9
-> In ∆OPA & ∆OCA
OP=OC (RADII)
AP=AC (TANGENT FROM EXTERNAL POINT)
OA=OA (COMMON)
So, ∆OPA ~∆OCA
=
√POA=√COA BY CPCT
SIMILARLY ∆ OQB IS CONGRUENT TO ∆OCB (1)
√QOB=√COB (2)
WE KNOW POQ IS A DIAMETER STRAIGHT LINE SO
√POQ=180'
√POA+√COA+√COB+√QOB=180*
√COA+√COA+√COB+√COB=180*
2√COA+2√COB=180*
2√COA+√COB=90*
√AOB=90*
PROVED.




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