C0+2C1+4C2+6C3...2nCn=1+2.2^n

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Binomial Theorem
  1. CIC Maths
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C0+2C1+4C2+6C3...2nCn=1+2.2^n 0:05:26

C0+2C1+4C2+6C3...2nCn=1+2.2^n

`c_1^2+2C_2^2+3C_3^2+....+n C_n^2=((2n-1)!)/([(n-1)!^2)`. 0:05:27

`c_1^2+2C_2^2+3C_3^2+....+n C_n^2=((2n-1)!)/([(n-1)!^2)`.

`(C_0-C_2+C_4-C_6.....)^2+(C_1-C_3+C_5-C_7........ )^2=2^n` 0:04:35

`(C_0-C_2+C_4-C_6.....)^2+(C_1-C_3+C_5-C_7........ )^2=2^n`

Catalan Numbers - 0:01:32

Catalan Numbers - Part 4

BINOMIAL THEOREM LECT-01 0:55:04

BINOMIAL THEOREM LECT-01 | BINOMIAL THEOREM DSSSB | BINOMIAL THEOREM SR SAINI | #binomial_theorem