Calculus 3 -- Cross product -- Practice

0:00 Introduction
0:47 Problem 1
7:40 Problem 2
16:32 Problem 3
23:13 Problem 4

[Hi_Brien]

For problem 3, I got a -13k from my cross product. I went the negative negative point to the more positive point route when drawing my vectors. That gave me 2 vectors <3, 4> and <4, 1> I'm not sure if that jumps out as anything weird there, but cross product time comes and you've got a (3-16)k there you should see something jump out -11k>-13k and '>' != '=' is a true statement. Why would the order of the vectors potentially change their cross product? And no combination of muliplying any pair of 4, 4, 3 and 1 and subtracting that pair gives you a -11. A 1-3*4 would bring us there, but it must be remembered that we need to multiply those elements, else we're multiplying by a zero, and then we're not gonna get a working answer there either. In this whole explanation the only thing I think makes sense as the error is the drawing of the vectors. Well I should sleep, I got a busy monday tomorrow. I even gotta figure out how to send a PDF from my phone to my laptop so I can send it in for a submission of my homework.

[Hi_Brien]

My professor didn't even get into determinates, and it made me sad. She was like "you don't need to learn that" and she gave us a FRICKIN FORMULA something like <a_x*a_y*b_z-...> she used 1 2 3 even... but yeah, thanks for the video!

[Hi_Brien]

You know, maybe I should be doing my actual homework, but I'm ahead, I can watch one of my favorite youtube channels instead

[zipar]

18:00 we're going dimensional oh shit