Coding Interview Questions and Answers | Python Interview Questions and Answers

Coding Interview Questions and Answers | Python Interview Questions and Answers
This video is part of Coding Interview Questions and Answers series .In this video,i have explained one more Coding Question with proper explanation. This question includes control sequences concepts.
Follow exception handling tutorial using below link..

1) Infosys Coding Question
2) Logical Questions in Python
3) Interview Questions and Answers

source code :-

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[techtricks.tech_]

test = 'aaaabbbccddddr'
output = ''
for i in range(len(test)):
if(test[i] not in output):
output = output + str(test.count(test[i])) + test[i]
print(output)

[sandeepdash]

6:23 In anaconda line no 12 is giving error " TypeError: 'str' object is not callable" .While doing the same in VS code it is not returning the last letter and last letter count ie for aaaabbbccdd its returning 4a3b2c. Its skipping d and d - count .

[simplyVeer]

str1 = input("Enter your input in the format of AAABBCCC: ")
s = set(str1)
l = []
for x in s:
l.append(x + str(str1.count(x)))
str2 = ''.join(sorted(l))
print(str2)

[unkownknown]

n="aaabbcdd"
#3a2b1c2d
fin=""
for i in n:

co=n.count(i)
if str(co)+i in fin:
pass
else:
fin=fin+(str(co) +i)
print(fin)

[nikitavhatkar]

Sir please make a video on this question

removing outermost parentheses from each primitive substring.

Input: S = “(()())(())()”
Output: ()()()

Input: S = “((()())(())(()(())))”
Output: (()())(())(()(()))

[suchandankhan]

a= 'aaaabbbccd'
out=''
for i in a:
count=0
for j in a:
if i ==j:
count+=1
if i not in out:
out+=str(count)+i
print(out)

[tpadma]

word = 'aaaabbbccd'

unique = sorted(list(set(word)))
print(unique)

lista = []
for i in unique:
lista.append(word.count(i))
print(lista)

output = []
for i in range(len(lista)):

print(''.join(output))

[AbhishekKumar-ppth]

Bhai ap mast samjate ho please or video dalo na program ka

[RoyalSuperCell]

input="aaaabbcccn"
c=''
for i in input:
if i not in c:
c+=i
for i in c:
v=input.count(i)
print("".join((f'{v}', i)), end="")

[NiteshSingh-vwin]

in Python.
a=True, True, True
print(a)
output - (True, True, True)
a == True, True, True
output - False, True, True
why given False ?

[gourikalahal]

for i in s:
if i not in d:
d=d+str(s.count(i))+i

print(d)

[PushpendraLowanshi]

sir agar str1="aaabbbazccz" isko kese solve karenge.

[dhananjaysingh]

inputs="aaaabbbccd"
output = "4a3b2c1d"

# using list
newdata=[]
outputfirst=""
for i in inputs:
if i not in newdata:
newdata.append(i)
for j in newdata:
count=0
for k in inputs:
if j==k:
count+=1

outputfirst+="{0}{1}".format(count, j)
print(outputfirst)



#using

outputseconds=""
dicts={}
for i in inputs:
dicts.setdefault(i, []).append(i)

for j, k in dicts.items():
outputseconds+="{0}{1}".format(len(k), j)
print(outputseconds)

[ganeshpal]

Sir ager questions aaaabbbaaccadd aa jaye to kya karna chahiye

[anusreekp]

# input :"aaaabbbccd",
# output :"4a3b2c1d"
Another way

new_dct={}
str1="aaaabbbccd" # p =
for s in str1:
#print(s)
if s in new_dct:
cnt=new_dct[s]
new_dct[s]=cnt+1
#print(cnt)
else:
new_dct[s]=1
print("new_dct", new_dct)
final_str =""
for k, v in new_dct.items():
final_str= final_str+str(v)+k

print(final_str)

[nishantraj-essl]

a="aaaabbcccaj"
b=""
c=""
count=0
for j in a:
if j not in b:
b=b+j
for i in range (len(a)):
if j==a[i]:
count+=1
c=c+str(count)
count=0
print(b)
print(c)
d=""
for i in range(len(b)):
d=d+c[i]+b[i]
print(d)
First time I code something 😅


p=dict()
d=""
count=0
for i in a:
if i not in d:
count=1
d=d+i
else:
count=count+1
p[i]=count
print(p)
str1=''

for h in p:
str1+=str(p[h])
str1+=h
print(str1)

[Viveksoftdev]

s='aaabbbazccz'

result = '4a3b2z2c'


s1 = lambda b:str(string.count(b))+b, string))
print(''.join(s1(s)))

[er.saurabbhkumar]

Bro how to connect with you
Your insta id and other platforms where I can connect with you

[hfkdnqh]

s="aaabbbcccdddz"
newstr={}
for i in s:
if i in newstr:
newstr[i]=newstr[i]+1

else:
newstr[i]=1
ls=[]
for k, v in newstr.items():
d=str(v)+k
ls.append(d)
print(''.join(ls))