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How to Graph the Equation y = 1/x (y equals one over x)

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In this video where we're going to graph of the equation y=1/x.
We'll start with the completed graph on-screen and we're going to work backwards. That means the graph for y = 1/x has already been completed and we're going to try and understand how it was constructed.
Let's start with the equation y=1/x. One thing to note about this equation is that we can put in any value for x and find the corresponding value for y. This means that we can plot any point on the line by selecting a value for x and then finding the corresponding value for y.
For example, if we put in x=1, we get y=1/1=1. So, the point (1,1) is on the graph. Similarly, if we put in x=2, we get y=1/2=0.5. So, the point (2,0.5) is also on the graph.
We can repeat this process for any value of x and find the corresponding point on the graph. This is because the equation y=1/x defines a curve that passes through all of these points.
So, there you have it the graph of y=1/x by working backwards. Remember, we can put any value in for x and find the corresponding value for y, and that point will be on the line.
We'll start with the completed graph on-screen and we're going to work backwards. That means the graph for y = 1/x has already been completed and we're going to try and understand how it was constructed.
Let's start with the equation y=1/x. One thing to note about this equation is that we can put in any value for x and find the corresponding value for y. This means that we can plot any point on the line by selecting a value for x and then finding the corresponding value for y.
For example, if we put in x=1, we get y=1/1=1. So, the point (1,1) is on the graph. Similarly, if we put in x=2, we get y=1/2=0.5. So, the point (2,0.5) is also on the graph.
We can repeat this process for any value of x and find the corresponding point on the graph. This is because the equation y=1/x defines a curve that passes through all of these points.
So, there you have it the graph of y=1/x by working backwards. Remember, we can put any value in for x and find the corresponding value for y, and that point will be on the line.
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