Finding a parametrization for a curve

Linear parametrizations, trigonometric parametrizTions

[shalomfadullon]

this video saved my life, cleared my skin, and watered my crops. THANK YOU stradermath

[GweenBarbie]

im still confused about b and why your're using sine and cosine?

[taylorebecker]

"People are asking questions when they aren't supposed to" :|

[jaeh]

not a great explanation because your parametric equations just "appeared"

Both points need to be converted into vector form. In this case our vector form is
<3-(-2), 4-(-5)> or <5, 9>

to formulate a parametric equation, we should need to choose a point. Let's make our point (-2, -5)

x(t)=-2+5t because we are using the x component of our chosen point and substituting it with our x component in the vector <5, 9>
y(t)=-5+9t because we are using the y component of our chosen point and substituting it with our y component in the vector <5, 9>

these equations do not just appear
many of your viewers including myself do you know how you got these equations because you simply did not explain them.

but thank you for posting these videos.

[dr.ahmedal-rubaiee]

Why you used sine and cosine for X and Y? You depended on which theory to do that?

[md]

The word is pronounced per-AM-e-ter-ize! Just say the word parameter normally and just add "ize" to the end.

[franciscunningham]

Your parameterization of the circle is wrong. Initial condition of y does not match up.

[david_m]

Extremely poor job of explaining how you get x in terms of it. I basically hear it as "this is what the manual says" because you didnt mathematically show how you got x in terms of t.