Let ๐‘ฅ=๐‘ฅ3+๐‘ฅ2โˆ’16๐‘ฅ+20(๐‘ฅโˆ’2)2๐‘–๐‘“ ๐‘ฅโ‰ 2๐‘˜๐‘–๐‘“ ๐‘ฅ=2 . If ๐‘“(๐‘ฅ) be continuous for all ๐‘ฅ, then ๐‘˜ =

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ะŸะพะบะฐะทะฐั‚ัŒ ะพะฟะธัะฐะฝะธะต
Let ๐‘ฅ=๐‘ฅ3+๐‘ฅ2โˆ’16๐‘ฅ+20(๐‘ฅโˆ’2)2๐‘–๐‘“ ๐‘ฅโ‰ 2๐‘˜๐‘–๐‘“ ๐‘ฅ=2 . If ๐‘“(๐‘ฅ) be continuous for all ๐‘ฅ, then ๐‘˜ =
(a) 7
(b) โˆ’7
(c) ยฑ7
(d) None of these

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ะ ะตะบะพะผะตะฝะดะฐั†ะธะธ ะฟะพ ั‚ะตะผะต
Let ๐‘ฅ=๐‘ฅ3+๐‘ฅ2โˆ’16๐‘ฅ+20(๐‘ฅโˆ’2)2๐‘–๐‘“ ๐‘ฅโ‰ 2๐‘˜๐‘–๐‘“ 0:00:34

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