A-Level Maths: J5-03 [Vectors: Vectors Problem 3]

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I did it a different way which I found less complicated.
First I found the magnitude of the vector AB, which turned out to be sqrt(52). Then I divided the components, (6i and 4j) by the magnitude to get the unit vector (6/sqrt(52)i - 4/sqrt(52)j). Then multiply by 4 to get 4 units, (24/sqrt(52)i - 16/sqrt(52)j). Then add and subtract accordingly into the coordinates of A to get the 2 possible pairs of coordinates for C.
Is this correct? Much appreciated!

bingot
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If it is only 4 units +- of C, would it not just be 2 - 4 and 2+4 to get the x co-ordinate?

akshitamodi
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On the question on K, how many marks would that be?

_GShock_