In a quadrilateral ABCD the linesegment bisecting `angleC and angleD` meet at E. Prove that `a

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In a quadrilateral ABCD the linesegment bisecting `angleC and angleD` meet at E. Prove that `angleA+angleB=2angleCED.`

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You have drawn parallelogram but a quadrilateral cannot be parallelogram always, so is that compulsory to have 180° as their sum of adjacent angles?? Please mam answer me I have this doubt

udyatiDas