Show that function f(x)=x²sin1/x is of bounded variation on [0,1] , Real Analysis -||

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today I explain concept of
show that function f(x)=x² sin1/x is of bounded variation on [0,1].
Real Analysis -||
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Wrong solution as sin(1/x) will undefined when x=0 sand you find the domain is [0, 1] but that can't be happen so the domain for f' will (0, 1] and we also need to show that f is continuous on [a, b]

SATYAMJANA-xdcv
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Can some help me with this question
Find the positive, negative and total variation of the function root x sin (1/x) for xx not equal to 0 and f(0)=0
Also f(x)=x^2sin (1/x^2)

kesharnathdhakal
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Mam kindly yh bta dayy kay x2sin1/x ka derivative kasy lia hai

usamashehzad
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A.a miss function ka derivative wrong hai book Mai yeh derivative hi liya gya hai partition nhi

hamzamughal
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Mam is ka derivative sai nai h or mam agr partition b ki h to is trha nai a raha plz is k bary ma Bata dyn

samraarshad