Prof Bonfert-Tylor, many thanks for your great lectures.
probono
My first lecture in my Complex Analysis went over the topology of C and it was very confusing and terse. This video helped a ton, thank you!
mohamedtlili
this is a hard topic to understand, but if u come across this, the world is yours. Thank you, Professor!
johnq
Thanks prof for such great series of lectures .
emc
The information is not exactly in the same order, but your lectures are a great supplement to CA by Gamelin. Thank you for your hard work!
ghostzart
thank you so much. Because your great lecture and I love complex analysis.
seanc
I doubt the theorem she gave that a subset G of C is connected iff any two points in G can be joined in G by successive line segments. I think the latter statement is equal to the definition of path - connectedness, so I guess that the topologist's sine curve can be a counterexample for that theorem(the graph of topologist's sine curve is a subset of R^2 which is isomorphic to C thus the graph can be regarded as a subset of C). Am I right? or Did I have any serious mistake???
taegyukang
how can I have this notes I mean this power point
salumuhamisiramadhani
so do the complex plane contains negative infinity... since R is a subset of C ? Or is it like R is an open set and infinity is its boundary so C contains R but not its boundary Pos. and Neg infinity..:)