3.30 | A rugby player passes the ball 7.00 m across the field, where it is caught at the same height

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A rugby player passes the ball 7.00 m across the field, where it is caught at the same height as it left his hand. (a) At what angle was the ball thrown if its initial speed was 12.0 m/s, assuming that the smaller of the two possible angles was used? (b) What other angle gives the same range, and why would it not be used? (c) How long did this pass take?

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That one you can also solve by using the formulas: Vx = Rx / t and Vfy = 0 = Voy - g(t/2). Isolate t and combine the two equations. Then you have to use the trig identity sin(2x) = 2sin(x)cos(x) to solve

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Ray Romano is my favorite Physics tutor

MAScreech
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How did you come up with those 2 formulas?

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