SURFACE AREA AND VOLUMES in 30 Minutes || Mind Map Series for Class 10th

Batch Description:-
1 Class -10th Mind Map Revision Series is Going on for English, SST, Maths & Science.
2 Each Chapter will be covered under this series.
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[icy_]

Guys chalo subhe tak Pooja karte he atleast pass hojaye

[ShibaMT]

25:15 :- cuboid hai sir 👍🏼, koi nahi, accha samjhaya aapne ✨
Who are watching one day before exam 😂😂

[mitalikalburgi]

25:35

Solution:
Dimensions of the cuboidal solid metallic block are 
15 cm× 10 cm ×5 cm

Radius of the hole =7/2 cm
Height of the cylinder =5 cm
Length of the block l=15 cm
Breadth of the block b=10 cm
Height of the block h=5 cm

Therefore,
Surface area of the block =2(lb+bh+hl)
=2(15×10+10×5+5×15)
=2(150+50+75)
=2×275
=550 cm²

Area of circular holes on both sides of the cylinder =2×πr²
=2×227×(72)2
=77 cm²

Surface area of the cylindrical hole =2πrh
=2×227×72×5
=110 cm²

Therefore,
Surface area of the remaining block
=550−77+110
=660−77
=583 cm²

The surface area of the remaining block is 583 cm2

[animesh]

I am studying this chapter for the first time and tommorow is my final board exams 😢😢😢

[soniarana]

I have my preboard today, a quick revision to maths was highly required, the video helped me the most for that. Thankyou so much ❤

[kartiknapte]

Studying on 11/3/24, it's exam dayy😢

[strideeeee]

11/03/2024 Maths exam ke liye jo dekhrha hai like karo😂

[PrathameshKhande-xgbr]

WATCHING THIS PEACEFULLY 2 DAYS BEFORE BOARD EXAM😅😅

[Eren_yeager]

Who are studying before one day of exam 😂

[adarshsrivastava]

Watching this video 1 day before board exam 2024😂

[the_bless_soul]

Watching 3 hours before today's maths board exam... 🙂
All the best guyss❤🌹

[Ananya]

For those who are unable to tackle question 4th here's the answer:-

We are provided with the information that a cylindrical figure is scooped from the cuboid, and we have to find the surface area of *remaining* solid

First we have to add all the sides of cuboid that is total surface area of cuboid then subtract 2×area of 1 circle from it ( because from the upper and lower surface of cuboid the circular portion of cylinder is scooped out so both the base will have circular holes in it so the area of both the circles will be subtracted from total surface area of cuboid) then we have to add curved surface area of cylinder (since we can touch the lateral surface of cylinder that is scooped out of cuboid )

So the derived formula is :-
2(lb+bh+hl)-2πr(r-h) [ taking 2 and (-) common] and the answer is 583

[rishabhrai]

20:58 Sir Q1 mein hollow diya hai to 2 se multiply karna hoga

[velocxty]

ABSOLUTELY TREMENDOUS revision session sir!😃👍💪⚡️

[sagunmishra]

Ek raat pehle shuru kiya hai wish kro ki 60+ aa jaye 🥲🥹

[guxyicziiu]

Board exam is near no need to fear becoz sir is here 😀

[AKHILYadav]

Kis kis ko 80%+marks lana h 😌😌😌 average students ko ❣️🥺like kro abhi log

[rishabff_]

Attendence laga Dena brother and sister who watching this one night before maths examination 😅😂

[manjeetsehrawat]

I wish all pass were pass in maths exam

[ForzaferrariLH]

Sir, there is a mistake in PRACTICE PROBLEM-4 (at 25:20 time). That [TSA of Cuboid + CSA of Cylinder] - [2πr²] Since the area of 2 circles is removed from the surface of the cuboid .