Algebra - Ch. 26: Solving Problems with Quadratic Equations (2 of 11) Skid Marks Ex.2

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We will find how far did the car travel if the skid marks=12ft in length given:
d=(1/10)v^2+v (v in mi/hr)

Next video in this series can be seen at:

[RmnHmn]

actually given the roughly accepted friction value of tires sliding on asphalt of 0.7, the speed of a vehicle sliding 120 feet would equate to about 50 miles per hour(sqrt 30df...d=distance slid f= friction value)

[tebogotema]

Good Day Sir May You Please Share Me Your Link Where I Can Get The Derivative Of Gauss’s Law In The Presence Of Dielectric [Use
Closed Integral P.da = −Qb]

[tsoojbaterdene]

Free fall acceleration of Venus is 8m/second squared. A person jumps 6 meter high on the earth and what disdance will the person jump on Venus?I hope you will answer my question.🙏🙏🙏

[GooogleGoglee]

Question: why the weight or mass of the car is not involved here?
Obviously if the car has more mass it would have means it was going slower and instead if the mass of the car was lighter than it would have means that the car speed was higher. Is it right?

[ptyptypty]

sorry Michel, but I'm about to get totally JUVENILE here.... I busted out laughing when you started out your video by saying, "Let's do an example about Skid Marks" .... not sure if your background would know what "Skid Marks" refers to in the USA... but .. lol, that's all I'll say...