Frequently Asked Python Program 10: How To Remove Nth occurrence of the word from a List

Topic : How To Remove Nth occurrence of the word from a List

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[vedanthasm]

what if we need to delete last word in the list?. not possible because of --> len(list)-1

[gtaburn]

easier method would be using inbuilt function count in list .if count>1 then remove that element from list. easy

[priyathiruvathuru]

How to do if string given like this .. str1 = "programinpythonprogram"
Here word "program" is occurs twice.

[abhisheksrivastava]

len(mylist)-1 is not correctly explained.

[gopinadhvulcni]

Sir directly we can the remove keyword

[shadow_self]

the code is not correct. nth occurence is there in the last part

[uybfkzo]

Thank you for posting the series. Very useful.

A small correction might require in the program. If the list contains many "geeks", this will not work well.
We will be getting an "Index" exception.

Ex:
mylist = ["geeks", "for", "news", "geeks", "paper", "geeks", "lake", "geeks"]
print(mylist)
word = "geeks"
n = 2

count = 0
for key in range(0, len(mylist) -1):
if mylist[key] == word:
count = count + 1
if count == n:
del mylist[key]
print(mylist)

[mohamedismail]

I use the code but it will create an error if we have occurances more than 2, because of index out of range. I would prefer below method.

my_list_1 = ["geeks", "for ", "geeks", "geeks"]
def remove_duplicte(lst):
seen = set()
result = []
for iteam in my_list_1:
if iteam not in seen:
seen.add(iteam)
result.append(iteam)
return result

[sasidharnaidu]

You can use enumerate function here

And break statement to end the loop after deleting the nth occurrence

[shivamani]

Hello sir
can u expailn this program ...
Q is : Given a string, write a program to remove all the words with K length.
input is : Tea is good for you 3
expected output is : is good

[LearningBigdata]

This one is not working. Please find the code below and also the output and suggest.

mylist = ['Geek', 'for', 'Geek']
word = 'Geek'
n = 2
count = 0
for i in range(0, len(mylist)-1):
if mylist[i] == word:
count += 1
if count == n:
del mylist[i]

print(mylist)


Output: ['Geek', 'for', 'Geek']

[SantoshKumar-kgsx]

Nice video however there is one correction. Code would not work if n'th word is at last index.

[kvelez]

how to reverse a word in list:

arr = ["hello", "world"]
for i in arr:
if i == "world":
print(i[::-1])

arr = ["hello", "world"]
for i in range(len(arr)):
if i == 1:
word = arr[i][::-1]
print(word)

[shivashankaramalakanti]

l=["geeks", "for", "geeks"]
a=list(set(l))
print(a)

[digitalcreator]

This code is not removing 2nd geeks...
In the first example you have shown 2nd geeks should be removed but fails..
i/p: ["geeks", "for", "geeks"]
o/p: ["geeks", "for", "geeks"]---which is wrong..

[jmgcheng]

my_list = [1, 2, 3, 3, "geeks", "for", "geeks"]
my_list = list(set(my_list))
print(my_list)

[kvelez]

Remove words in list:

arr = ["hello", "world"]
for i in range(len(arr)):
if i == 1:
arr.remove(arr[i])
print(arr)

arr = ["hello", "world"]
for i in arr:
if i == "world":
arr.remove(i)
print(arr)

arr = ["hello", "world", "world"]
dictionary = {}
for i in arr:
if i in dictionary:
arr.remove(i)
dictionary[i] = dictionary.get(i, 0)
print(arr)

arr = ["hello", "world", "world"]
dictionary = {}

def counting(arr, dictionary, i):
if i >= len(arr):
return f"\nArray: {arr}\nDictionary: {dictionary}"

if arr[i] in dictionary:
dictionary[arr[i]] += 1
arr.remove(arr[i])
else:
dictionary[arr[i]] = 1
return counting(arr, dictionary, i+1)

print(counting(arr, dictionary, 0))