Probability 02 | Conditional Probability | Class 12th/CUET

📝 For complete notes of Lectures, visit SANKALP 2023 Batch in the Batch Section of PhysicsWallah App/Website.

-------------------------------------------------------------------------------------------------

NOTE: This batch is completely FREE, you just have to click on the "BUY NOW" button for your enrolment.

🔴 Batch Details:-

✅ FREE Course for Class 12th (Board + CUET)

1. This free batch is for the students aiming Class 12th (Board + CUET).
2. The best faculties of India will cover full syllabus of each subject.
3. All the classes will be provided in Recorded form only on our YouTube Channel Ncert Wallah.
4. Class Notes of each lecture will be provided on our PW App in respective batch in PDF format.
5. Practice sheets with text solutions of each lectures will be also provided on App.
6. Weekly Schedule of classes will be posted on Community and announcement section of Batch.

------------------------------------------------------------------------------------------------

📌 PHYSICS WALLAH OTHER CHANNELS :

📌 PHYSICS WALLAH SOCIAL MEDIA PROFILES :



#Probability #NCERTWallah #PhysicsWallah #CUET #CUETMaths #Class12Maths #ProbabilityClass12th #ConditionalProbability

[NCERTWallahPW]

📝 For complete notes of Lectures, visit SANKALP 2023 Batch in the Batch Section of PhysicsWallah App/Website.

[NDA]

Sir pichle lecture me isliye 27/30 aaya tha becoz wo probability ka sum h na ki kisi single probability ka value h

[vrishankkkk]

q4 is wrong i guess,
the answer should be 7/11*13*3 and not 7/11*13*13

[Deepanshi_yadav_]

Sir hum ques -3 ko aise bhi toh kar skte hai...
A: two balls are drawn
{BW, BB, WW, WB}
B: first is white and second is black
{WB}
toh according to conditional probability
P(B|A) = n(A inter. B)/n(A)
= 1/4
Tab bhi same ans ara hai
Hw que :- 3/8
Sir lecture was awesome 🎉🎉🎉🎉... thank you

[NDA]

Love u sir 💕 sir aap such me sbse best teacher h 😇🙏

[AliKhan-uqlc]

I did qno3 using conditional probability concept

A : {WB, WW, BW, BB} = 4
B: {WB}
P(A intersection B) = {WB} = 1
P(B|A) = P(B intersection A)/P(A) = 1/4

[arceus]

Thank you sir concepts clear ho gye



Ha aaj 7 march hai😅

[sujitdubey]

31:15 sir i think you have made a mistake in this question in calculation it will be 7/13.11.3 = 7/429 and it will be P(A intersection B) = P(A).P(B)

[sonalijain]

Jisne boards ke liye kuch bhi nhi padha toh bss vijeta series ko follow karlo 90% se jyada score ho jayega👍🏻🔥

[sdeep]

Bahut dikkat dayak chapter hai probability