Graphing Hyperbolas in Standard Form

I introduce the basic structure of hyperbolas discussing how to locate the vertices, foci, transverse axis, conjugate axis, asymptotes, etc. I finish by working through multiple examples.

[georgiadavidson]

If only you could teach at my school. Thank you for creating such amazing and easy to understand videos. I see light at the end of the tunnel in my math class now because of you :)

[profrobbob]

THANK YOU for taking the time to let me know how much help you felt my videos provided you. And yes, it is still amazing to me that I am literally teaching students in over 120 countries...BAM!!!
Thank you for being such a loyal viewer and please continue to share your experience with others so I can continue to grow and share my lessons with them:D

[profrobbob]

THANK YOU for that most complimentary comment! This channel has now become like a second career along with my full time teaching job. My wife and I are putting everything we have into it with the hope of making it the next big "go-to" YouTube Math Channel!!! So please accept the challenge to spread the word to everyone you meet that would benefit from my videos through the duration of your continued academic career :D

[profrobbob]

We (teachers) have our own teaching style and sometimes it just takes anothers point of view to "get it"! I'm happy to hear that while seeking extra help you decided to watch my videos and found them so helpful. And remember, you can be my student "anytime" you want to tune in and watch another video:) Good luck next week!

[profrobbob]

Thank you for watching, for subscribing and for "liking" my videos! I appreciate that you admire the time and energy that goes into each one of my videos. I love what I do and when I hear comments like yours it makes it easy to continue this journey. Please share with your friends...my channel growth comes through the support of my subscribers...thanks

[profrobbob]

I am so glad you liked my video so much:D I hope you continue to find them helpful as you work through your class. I hope you do great! Don't worry because I am not going to stop making videos now...I am having to much fun. Please help me out by spreading the word.

[profrobbob]

That's GREAT news...and you are so welcome. You know it takes the initiative on your end to seek out extra help in the first place and that is a wonderful attribute!! Thank you for your continued comments and support, that tells me you are still watching and learning from my videos:)))

[profrobbob]

Thank you for the great feedback. I am thrilled I could help. PLEASE tell your teacher I said thank you as well. I am really enjoying making this math channel and I appreciate the support!

[profrobbob]

I'm so glad to hear that you are enjoying my videos and my humor =) Sounds like you have a full academic schedule! Thanks for subscribing and please be sure to share my channel with your friends too:D

[BWithEmMarie]

thank you so much! I just watched all 4 of these videos and I finally understand!!!! thanks :)

[profrobbob]

This is what happens when you love what you do!
CONFUCIUS says: "Choose a job you love, and you will never have to "work" a day in your life!"

[profrobbob]

A lot of what you said in your second paragraph is only correct if the hyperbola opens horizontally. If you rematch the beginning of the video you will see I introduced two standard forms. You should write the equation of the two asymptotes as one equation in Point Slope form since the two asymptotes share the same common point, the center of the hyperbola. If you know the center and c, you move from the center a distance of c to find the foci....and move in the same direction of a.

[profrobbob]

I'm glad you searched YouTube for extra help and choose my channel to watch and learn from! I appreciate the awesome comment, support and viewership but speaking as a classroom teacher...don't give up on your class, use it as an additional learning tool...maybe you could even watch a lesson ahead and maybe answer questions in class and help your teacher:)

[profrobbob]

You're welcome. I'm happy to hear that my video was helpful enough for you to finally "get it"...I love those moments in life when the light comes on:) Thanks for supporting by subscribing and liking...and please be sure to share my channel with others who might benefit as you did...and help my channel groW and that will help to make my day!

[profrobbob]

Great news for you...I will be teaching AP Calc next year and just started building on my Calc library again:) I'll be looking forward to that meeting! (and you're not that far away)...and when you're friends start asking where the BAM! came from I hope you'll take the opportunity to tell them about my channel and continue to help me groW!

[profrobbob]

That is why I finished with solve the equation...with cross multiplication. The a/b fraction in the equation of the asymptotes is in reduced form. Keep trying and let me know if you still can't figure it out. A is 4 in your problem.

[profrobbob]

Yes...since your vertices are vertical the slope of your asymptotes are +- a/b. You need to determine where the center is, figure out "a" from the given information, then set up a/b=2/3 to solve for "b"

[shizukuchan]

Be my professor! arf arf. Love your teaching techniques.
P.S. Not boring. ;)

[profrobbob]

The two general drawings at the beginning of the video, the horizontal hyperbola on the left and vertical on the right? The orientation for those is correct.

[profrobbob]

Thanks for commenting again so I could THANK YOU for liking, supporting and subscribing.
Now BAM!...go get that "A" on Monday, and let me know how you did!