one beautiful inequality problem | INEQUALITY SERIES |

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it's a straight application of holder's inequality followed by am gm

adamboussif
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Actually you can just expand the terms and you will get abc+a+b+c+1/a+1/b+1/c+1/abc which is obvious by AM GM ≥ 8(1)^(1/8)=8.

rendyadinata
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Very nice mister 👍
Best regards from Belgrade, Serbia 🇷🇸

darkomarkovic
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