C program to check if the given number is a natural number | Coding safari

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Write a c program to check if the given number is a natural number | Coding safari

In this C programming tutorial, we present a simple program to check if a given number is a natural number. The user is prompted to enter a number, and the program determines if it is greater than zero. By utilizing conditional statements, it provides a clear output indicating whether the number is a natural number or not. Join us to understand the concept of natural numbers and enhance your coding skills with this easy-to-follow program.

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This updated code handles the decimal edge case also! 🙌

#include <stdio.h>

int main() {
float number;

printf("Enter a number: ");
scanf("%f", &number);

// Check if the number is a natural number.
if (number > 0 && number == (int)number) { // checks if the number has no decimal
printf("%.2f is a natural number.\n", number);
} else {
printf("%.2f is not a natural number.\n", number);
}

return 0;
}

coding_safari

it is wrong because when we give 1.1 or any decimal as input it will give natural number as out put which is not an natural number( because of typescript)

Krishna-lnol

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