Ex-10.2 Q-1,2,3| Chapter 10 | NCERT | Class 10th Math |

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Ex-10.2 Q-1,2,3 Chapter 10 NCERT Class 10th CBSE/ICSE/HBSE All State Board Easy Method By Deepak Antil Sir

Ex-10.2 Q-1,2,3| Chapter 10 | NCERT | Class 10th Math |

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Sir Just one word for your teaching OUTSTANDING 💚💚that's all i can say💙

mirfalak
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Thank u sir u r our only helping frnd for board 💟

ankitmaurya
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Tq sir ye video main apne dosto ko send krunga and sabko bolunga ki subscribe kre aapka channel

bantaixclub
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Sir everything is Amazing! But when you say, chaliye start krtay hain beta exercise 10.1, very sweetly seriously it touches my heart ❤️💜 the beta word you say gives lot of respect to all those students who are watching your videos 💯💯🥀❣️❣️👌👌

Yashikasharma
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SIR ACCORDING TO ME IN Q3. RHS CRITERION WAS TO BE USED BCZ THE ANGLE WHICH YOU HAVE TAKEN IS NOT BETWEEN THE 2 EQUAL SIDES . KINDLY CHECK IT ONCE . THNK U ...

hardhikyt
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Best teaching !! 👍 don't know why, people disliked this video

kanvi
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I am also using same pen 🖊 like sir for this 🤣🤣🤣

myensbrave
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Sir aap bahut achha read karva te ho👍👍👍

its_ur._raj
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You r solving maths in easy process sir 😍

rogmentis
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Sir ek bar me mind me aa jate h question

hrshortmaster
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I know sir you are writing on a waste or unused paper ✨👍 and thats is too good 💟🌼🌟

manii_prajapati
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Mera syllabus complete, sample papers complete, pyqs complete, rd sharma complete,
Now i can take relax😤😊😊
And Practice to become topper😮😊

kattarhindu
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☺️☺️ Thnx sir ☺️☺️
☺️☺️ Great explaination 😊😊

hemantsaini
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Are you great sir and thank you so much sir 😊🥰❣️

ravijangid
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Aap bhoot acha smjhate ho sir ji❤❤❤❤❤❤

sivam
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Thank you so much sir for helping me because of you i got a lot of help to question 🤗

arshansari
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Sir aap to bina into ka sidha point pe aata ho thnku sir

BTGamer
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Sir, I guess it's supposed to be rhs congruence rule in Q3. Cause the angle is not between the sides

uddipta
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Q-2 me PT and QT tangents hai, PQ kaise tangent ho gaya ??

ItsVivuworld
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Sir, in question 3 can we do by the method as to extend line AP to point c and as angle OAC= angle APO +angle AOP(EXTERIOR ANGLE PROPERTY OF TRIANGLE)
OAP=90, APO =½APB=40
OAP+OAC=180
OAC=90
OAC=AOP+APO
90=AOP+40
AOP=50

himanshurathod