Leetcode 70. Climbing Stairs [Java] | Two best approaches

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Check out how to solve the leetcode 70 Climbing Stairs question in Java. This is one of GOOGLE's most commonly asked coding interview questions according to Leetcode. In this video, you will see two possible solutions which both are faster than 100% of the leetcode submissions.

Please write in the comments below which leetcode problem you want me to solve next.

And remember, a leetcode a day keeps unemployment away!

Thanks for watching!
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Thank you for this video! I am still learning about time complexity and I was wondering how your solutions differ from what I came up with =>
const steps = (n) => {
if(n === 0 || n === 1) return 1;
return stairs(n-2) + stairs(n-1);
}

JasonGarcia-xd

Thank you, bro. It's very helpful now.

maksymr.

why do we need to specify the n==1 case?
if (n <= 1) {
return 1;
}
isn't dp[1]=1; is already for n=1 case?

cinemafellaz

Нихрена не объяснил. Чисто заготовку напечатал

Steklopod

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