Example 2 - Chapter 8- Class 10 | Introduction to Trigonometry | NCERT Maths | CBSE

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Example 2 : If ∠ B and ∠ Q are acute angles such that sin B = sin Q, then prove that ∠ B = ∠ Q.

In this tutorial, you will find the explanation of the following:
Example: 2
Class: 10th
Chapter: 8, Introduction to Trigonometry
Textbook: NCERT
#Class10Math #Class10Maths #TrigonometryClass10

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Sir The background And Your Explanation Is Too Good ✌✌🙏🙏👏👏👏👏👏

letssee
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Thank-you for the great explanation sir! 2023-2024 batch

meleni
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Sir, instead of using sss, we can use sas becaus angle b and angle q both are 90 degree

kirantripathi
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best video sir till i watch on youtube

electrouniversgamer
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Sir i have a doubbbt
Cannt we solve this ques by taking only single triangle for example ∆ABQ whichh would be easier is this method correct ???

DeepakYadav-dgvi
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Sir can you tell me some important questions of this chapter

Alv
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Sir hum Hypotenuse se Perpendicular ko divide kyo karenge plz tell

reenaguru
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Sir, u have explained it very well 🥰
But I have a doubt,
Instead of proving both the triangles similar, can we also prove them congruent by ASS property?
And then by Cpct *angle B = angle Q

sanjanaaneja
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sir can we solve it using one triangle only like we did in ex 8.1 s 6th ques? it would be short and easy then ..

tanvithakur
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Can we apply RHS theorem instead? Since this way is quite diffucult.

maanitsingh
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Sir please keep making study videos for us

AMAN-lnug
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Sir apne PBP / HHB kyo likha hai iska koi use hai kya sir

reenaguru
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Hello sir, I had a doubt.
Can I say that AC / AB = PR / PQ (Given)
Therefore, this can be rewritten as :-

AC / PR = AB / PQ ---- (1)

Also, In ∆ACB & ∆ PRQ,

Angle ACB = Angle PRQ (Both are right triangles, therefore 90°) ---- (2)

Therefore, from (1) and (2)

∆ACB ~ ∆PRQ by SAS

Therefore, angle B = angle Q (Corresponding angles of similar triangles are equal)





👆 Is this way correct? 👆

MotivationMindsConquer
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Sir, instead of using sss, we can use sas becaus angle b and angle q both are 90 degree

kirantripathi