Programming Problem #4 - A Set of Beginner Coding Problems & Solutions

I am officially continuing the programming problems and solutions series. I am going to be posting a new programming problem each week! They will vary in difficult alternating between medium, easy and hard. These specific problems are for beginner programmers and next week I will introduce a more difficult problem.

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Tags:
- Tech With Tim
- Programming problems
- Computer science problems
- Coding problems
- Python problems
- Python Tutorials

[TechWithTim]

I know a lot of you will think these problems are very trivial...I promise the next videos in the series will show much more complex problems. I just want the beginners on the channel to get a chance to be introduced to some easy problems and have a place to practice their skills! Hope you all are looking forward to these weekly problems!

[DanielWeikert]

more on AI would be awesome. Especially concepts like reinforcement learning. Thanks for your videos. Great work Tim

[HostDotPromo]

Never seen these series before, pretty cool man. 😎

[sankethb.k]

Thanks a lot
Please upload more videos on problem solving

[olaniyioluseun]

Hi Tim, did you get to finish the tutorial on using Kivy to build mobile apps? Did you get to make it up to apk and run on a mobile phone?

[julyapetrenchuk]

Hey Tim! Can you please make 3D python tutorial like you can move around and all kind this stuff because on YouTube is only time lapses or final projects. Thank you!

[rajsalvi]

can you please make tutorial on making chatbot in python3.6?

[guilhermecosta]

Why does it need to be two equals signs at 13:55

[itsshopboy]

This is my second video on your channel

[tylerfusco]

My solutions, not counting function definitions (comment if I can make these shorter):
def string_times(s:str, n:int)->str:return s*n #10 bytes
def front_times(s:str, n:int)->str:return s[:3]*n #14 bytes
def s[::2] #13 bytes
def ''.join(s[:i+1]for i in range(len(s))) #45 bytes
def last2(s:str)->int:return sum(s[i:-2].find(s[-2:])==0 for i in range(len(s)-2)) #60 bytes
def l.count(9) #17 bytes
def 9 in l[:4] #17 bytes
def array123(l:list)->bool:return min(i in l for i in range(1, 4)) #38 bytes