Lecture 5 Module 3 Convolution Example Continuous Time

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Convolution Example Continuous Time
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I have seen various videos in order to understand the topic that into my mind after seeing the elaborate explanation in sir

sahanaravinder
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the great video i had a lot of confusions but finished in not more than 30 mins
you're life saver

mugusengajeannepo
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Bro I can actually understand you and hear you very clearly. Legend

irving
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When you reach the time period of {2 ≤ t ≤3} wouldn't the function in your integral be just 1? Since the area of convergence/overlapping occuring is just up to the amplitude (or just a square decreasing) of x(t) = 1?

jaimeayala
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Thank you for the explanation, good sir

NatPatrick-lw
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in case 2 how did u get the t^2 ? it should have been taken outside the integral sign because you are integrating with respect to tau

lisaprince
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Could one exolpalin to me why he didn't put 2 in equation of line is 2-t why in his integrations didn't put 2 ??

papammeheia
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your voice is similar to neso academy signals and systems teacher

premat.j.
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At 20:20, your integration is incorrect. I did it many times and got the same answer, but different than yours. I also checked it with online calculators.

bendustin
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how we got the integration at 18:08 please
and thank you

omerahmet-ru
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nice job sir shouldn't it be ((t)-(t^2/2)+(3/2))at 20:09

metea.
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if in the convolution I assume t=0, then how will you solve the integration?

utkarshkathuria
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The blue hatching is often wrong. It should run all the way up to the red response function h, wherever x is 1.

benheideveld
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Please someone clearly tell me how we are getting (t-2)on the left hand side after time reversal, I can not get that. In my sense it would be (t+2) but.
Please clearly tell someone shifting process after time reversal.

jamilajamila
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I want to ask, what software do you use in drawing this lecture?

Juan-iqbr
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Disappointing, too much playing about with the computer graphics.

philcooper
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I'm sorry to say there are a lot of mistakes in the explanations and even in the equations you gave at the end the function y(t) exists only between 0 and 1.

tshibengabukalonji