(21-50) A thin glass rod is a semicircle of radius R, Fig. 21-66. A charge is nonuniformly distribu

(21-50) A thin glass rod is a semicircle of radius R, Fig. 21-66. A charge is nonuniformly distributed along the rod with a linear charge density given by λ=λ_0sinθ, where λ_0 is a positive constant. Point P is at the center of the semicircle.(a) Find the electric field E (magnitude and direction) at point P. [Hint: Remember sin(−θ)=−sinθ, so the two halves of the rod are oppositely charged.] (b) Determine the acceleration (magnitude and direction) of an electron placed at point P, assuming R = 1.0 cm and λ_0=1.0μC/m.

[soumyapriyadatta]

Thanks a ton. You explained it so well and made a difficult question simple enough to understand