A uniform rod of length 200  cm and mass 500  g is balanced on a wedge placed at 40  cm mark. A m...

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A uniform rod of length 200  cm and mass 500  g is balanced on a wedge placed at 40  cm mark. A mass of 2  kg is suspended from the rod at 20  cm and another unknown mass ' m ' is suspended from the rod at 160  cm mark as shown in the figure. Find the value of ' m ' such that the rod is in 2  kg equilibrium. (g=10  m / s^2)
(a) 1/12 kg
(b) 1/2 kg
(c) 1/3 kg
(d) 1/6 kg
(NEET)

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Sir jis point pe rod balance hoti hai uska matlab vo hamara axis of rotation hota hai ?? Or usse axis of rotation ham sare distance likhte hai sabhi mass ke
Sir com ka position 100 kase hoga ...masses equal toh nahi hai dono side .

chanchal
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❤sir wo anti clockwise aur clockwise ultra lik diya

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