Evaluate lim(x→1) x/(x-1)-(1/logx) || limit x tend to 1 x/(x-1)-1/logx | ∞-∞ form indeterminate form

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indeterminate form
Evaluate
 limit as x approaches 1 1/x-1 -1/logx
[ ∞-∞ form ]
use l hospital rule

 lim(x→1) (1/(x-1)-1/log(x))

lim(x to 1) [x/(x-1)-1/logx]

infinity by infinity form

[ 0.∞ form ]

proof

proof

advance calculus chapter 3 indeterminate form all questions

#indeterminate_forms #indeterminateforms #lhospitalrule
#limitandderivative #limit

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