CommonCharacterCount | CodeFights Intro Algorithm JavaScript Solution and Breakdown

CommonCharacterCount | CodeFights Intro Algorithm JavaScript Solution and Breakdown
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[ilovepizza]

i used map and then converted to object and then did what u did from there

[positive-yd]

That's so awesome. I spend much time to handle the issue but can't solve, now I got it. Thank you so much, keep going Bro

[husamalsairi]

below is cleaner way,  
const commonCharactersCount = (s1, s2) => {
let string1 = s1.split('');
let string2 = s2.split('');
let arrayOftMatch = [];
string1.forEach(element1 => {
string2.forEach(element2 => {
if ((element1 === element2) && == -1)) {
arrayOftMatch.push(element2);
}
})
});
return arrayOftMatch.length;
}

[lakhanrochwani]

Just more refactored code:
function commonCharacterCount(s1, s2) {
const s1Count={};
const s2Count={};
let count = 0;
for(let char of s1){
s1Count[char] = s1Count[char] + 1 || 1;
}
for(let char of s2){
s2Count[char] = s2Count[char] + 1 || 1;
}
for(let char in s1Count){
){
count += Math.min(s1Count[char], s2Count[char])
}
}
return count;

}

[young]

Using objects makes the function kind of long. Here is what I did:

function commonCharacterCount(s1, s2){
var s2Arr = s2.split('');
var result = 0;

for(var i=0; i<s1.length; i++){
if(s2Arr.indexOf(s1[i]) !== -1){
s2Arr.splice(s2Arr.indexOf(s1[i]), 1);
result++;
}
}

return result;
}

[HowYoongJian]

Can this be solved with a map function?