Derivative of inverse secant function

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In this video, I showed how to find the derivative of inverse secant function. I also explained why it is necesseary to write the domain of the derivative.
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I like this! I have a question, though. Usually, the answer has the "x" in the denominator as "|x|", and that's what I don't understand. I half-understand it in terms of, you can't have a hypotenuse with negative length; but that feels like a condition one imposes because it "feels right", which isn't a great justification. Certainly, taking the absolute value because it makes the problem go away, is not very rigorous.

Are hypotenuses defined in terms of absolute value? Like, are they defined as a positive scalar derived from the interaction of two vectors?

kingbeauregard
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Hello teacher
Rnag of 1/cos(x)
=(-∞, -1)∪(1, +∞)

has not =(-∞, -1]∪[1, +∞)

if you substitute 1 or -1
that is UDF 🌼🌼🌼

time at 8:50

mhamadabdulla