Impossible Equation: 2 = 0? Find the Mistake! #maths

impossible | find the mistake #maths
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[indrajeetkundu]

√(a)*√(b)=√(a*b) if a>0 and b>0 here this rule violate

[prayagpr]

Mistake was √ab= √a √b. This rule has some conditions, you cannot blindly apply it everywhere(especially when complex numbers are involved)

[DangerZoneasesd]

Here everyone is saying that why we should not spilt root if no. Is negative.
Here is reason:
Ex. √-2*-2 = √4 = 2 know, -2 * -2 = 4)
Now if we do in split
√-2*√-2 = -2 .
Another example.
√-5*-5 = √25 = 5
√-5* √-5 = -5 .
That's why there is condition that value of a and b should be equal or greater than zero.

If you agree please like ❤

[SuperGamer_of_the_world]

The mistake is that the i² is not equals to -1
i²≠-1

[Srijanc-nzwf]

Here they have taken
sqrt((-1)^2)=-1 .
BUT, sqrt of any number has two roots.
Eg:-sqrt(4)=2 and-2.
So sqrt(1)=-1 and 1.
Therefore sqrt(1) is not equal to 1.
So, we can not replace 1 with sqrt(1).

[devanshtomarth]

You can't apply this rule when both of them are negative.

[THE_FRANXX]

911 :- what is your emergency sir
Me :- my math is not mathing
Finally! I become famous
Thanks for 956 likesss

[IambackRitam]

√a*b = √a * √b when
a > 0 and b<0
Or
a<0 and b > 0
Or
a>0 and b>0


Not,
a < 0 and b < 0 it's wrong.

[AbdulazizAziz-bliy]

Yes, , but the situation changes when you take

The square root of a negative number is not defined within the real number system. This is because no real number, when squared, will give a negative result. For instance, while, you cannot take the square root of and remain in the realm of real numbers.

Instead, the square root of is defined as the imaginary unit, where:

\sqrt{-1} = i

[rudrojitartscrafts]

√(a)*√(b) = √(a*b)
If a≥0 and b≥0
Here this rule violate

[blacktimes]

If both are negative the root-splitting rule doesn't apply.

[jitendragupta]

This is totally wrong, √-1 x -1 = √1=1
But you split into √-1 × √-1 which is equal to -1, how you convert 1 = -1 . if you spitting root there is a condition, I think this is a only reason .
If you agree like ❤

[mishaBehterevTOP]

i≠√-1
If i=√-1 then
-1=i^2=i*i=√(-1)*(-1)=√1=1
Then
-1=1

[wildanimals]

Two negative numbers are not multiply under root

[Learnwithgutz]

Remember 😂 i² = -1 only because √-1 × √-1 = -1

Edit: √-1 × √-1 ≠ √1 but = -1
Also .. √(-1×-1) ≠ √-1 × √-1 but = √1

[LordofDemon]

Toppers=telling solution

Back benchers =WTF

[AnnapurnaNeelannavar]

√a√b = √(ab)
fails iff both a and b are negative

[akanshverma-b]

2 = 2
2 = 1 + 1
2 = 1 + √1
2 = √-1 × -1
2 = √-1 × √-1
2 = (-1 × -1)^1/2+1/2 [• √ = ^1/2]
2 = (-1 × -1)^1
2 = -1^1 × -1^1 = -1 × -1
2 = 1
So the mistake was in the step 3 i.e. 2 isn't equals to 1 + √1

Context:- later in some steps u see i didnt use BODMAS/PEMDAS in brackets cuz it doesnt gonna effect my answer if i use the BODMAS/PEMDAS then still answer will be the same i.e. 2 = 1

[healthydietwithtastyrecipe]

Mistake occured bcz of the fact that √(ab)=√a√b only if a or b belongs to +ve integers but if both are -ve then this doesn't work.

[SnipeArt]

1 + 1 != 1 + √1. Since √1 can be 1 or -1. It is wrong in the very first step.