Assertion(A): Consider the function defined as f(x)=|x| + |x-1| , x⋳ R. Then f(x) is not differentia

Assertion (A): Consider the function defined as f ( x ) = | x | + | x − 1 | , x ∈ R 𝑓 ( 𝑥 ) = | 𝑥 | + | 𝑥 − 1 | , 𝑥 ∈ 𝑅 . Then f ( x ) 𝑓 ( 𝑥 ) is not differentiable at x = 0 𝑥 = 0 and x = 1 𝑥 = 1 .
Reason (R): Suppose f 𝑓 be defined and continuous on ( a , b ) ( 𝑎 , 𝑏 ) and c ∈ ( a , b ) 𝑐 ∈ ( 𝑎 , 𝑏 ) , then f ( x ) 𝑓 ( 𝑥 ) is not differentiable at x = c 𝑥 = 𝑐 if lim h → 0 − f ( c + h ) − f ( c ) h ≠ lim h → 0 + f ( c + h ) − f ( c ) h lim ℎ → 0 − 𝑓 ( 𝑐 + ℎ ) − 𝑓 ( 𝑐 ) ℎ ≠ lim ℎ → 0 + 𝑓 ( 𝑐 + ℎ ) − 𝑓 ( 𝑐 ) ℎ .
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