A Nice Olympiad Exponential Problem.

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Welcome to your channel. I hope you are happy, well and safe 😊 Today we will solve this math problem. Please feel free to comment if you have better ideas/methods to find the answer. If you think you gained some knowledge and want to support me, please "Like" the video and "Subscribe" the channel.
Thank you all 🙏❤️.
#exponents #maths #algebra #olympiad

[Mesa_Mike]

Could've saved a lot of writing by noting that if x were anything other than zero, that would imply 27 = 9, a clear contradiction.

[franckplanks]

X=0 easy knee jerk response to trivial problem

[bvideoz]

3x = 2x
3x - 2x = 0
x(3-2) = 0
x(1) = 0 - so either x = 0 or 1 = 0 ?
1 can't be 0 so it must be x = 0
What's so "Olympiadic" about this problem? 😁

[michaelbell]

You could explain this problem much better by drawing the lines 27^x and 3^x graphically. The only place they could possibly meet is on the x axis. Hence x=0.

[alinayfeh]

The alone clear answer 27^x=9^x (a^m)^n=a^(m+n) a>_0. x=0

[kanguru_]

27^x-9^x=0, so [3^(2x)][3^x-1]=0, so 3^x=1, so x=0.