Probability Tree Diagrams : removing items without replacement

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Thank you so much this was so helpful!
I have an exam tmrw and my teacher forgot to tech us this and we need it for the test so thank you!!!!

saraibgui
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You wrote b instead of w in the last branch

horrorayaan-
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One of the best teachers on YouTube. Thanks!!

amankataria
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This video just saved my life thank you 🙏🏽😭

lindagamibes
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Thanks so much this really helped my daughter

JaneOpondo-qqqs
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haven't you done it wrong?
it says that 2 were taken out, so it must be out of 10 not 11

christianacknowledgement
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hello! kind help me here: In batch of 100 screws, a maximum of 3 can be defective. A random sample of 20 screws are taken. How many defective parts are allowed in this sample considering all scenarios probabilities less than or equal to 90%?

angedieka
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Got my Maths GCSE exam tomorrow and your videos have helped me bump up my grade from a miserable D grade all the way up to a B/A grade! Thank you so much!

KeybladeWielderXV
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So, say I have a mixed packet of Sweet Bell pepper seeds that contains equal parts of 5 different varieties, what is the minimum number of seeds that I would need to plant in order to ‘guarantee’ that I’ve planted one of each variety. 80% of them + 1, right?But, what if I had a bucket of seeds?! That’s a ridiculous amount of Bell peppers.
So I thought, we’ll, I’m willing to utilize two rows in my seed starting tray. That’s 12 cells.
There are 39 seeds in the packet.
An equal 20%of each variety (orange, white, purple, yellow, and red) included in the packet, according to Burpee.
What are the “odds”, “%chance”, or “probability” (i’ve been thinking about this too long and I’m not even sure which I’m asking for anymore lol) that I will have planted at least one of each variety? This brain teaser has got me stumped.
Please and thank you

juanalocken
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Is it possible if we can simply again?

JoelynUwea-ytff
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can you upload with different number, I'm still confuse

muhamadapqoribinmohd.dzulk
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Send me answers for
A box contains 4 pink counters 3 green counters and 3 yellow counters . 3 counters are drawn at random one after the other without replacement .
(a) Find the probability that the third counter drawn is green and the first two are of the same color.

(b) Find the expected number of pink counters drawn.

akandwanahoblessing
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U took out one with no replacement yet the question says two

LucyNamukwaya-eojm
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Why did he use 1/3 to multiply at 2:26 though. Pls help 😭😭

Joy-ioup
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i konw very simple method

=8/33+8/33+8/33
=8+8+8/33
=24/33
thats it ☺☺☺

monarmatutul
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Bla bla bla BORING you seemed a bit worried too cuz the pen slipped from your hand 🤣🤣🤣

skstar