JavaScript Exercise 1: Solution & Shoutouts | JavaScript Tutorial in Hindi #26

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Comment "#HarryBhai" if you read this 😉😉

[ajaykharat]

Thanks You Harry Bhai !! I got the Rs 500 Amazon Voucher !! You're my Motivation & Inspiration !! You're such a great person !! 🙂🙂

[yusiferzendric]

You are uploading such precious content thats the biggest gift for us

[anshikabhargava]

Hi Harry,
Firstly, Thank You for all your efforts .
A small request - Please upload the videos daily .
I am really excited to finish the course early. You have made the programming so easy to understand and implement.
I am waiting to understand closures, prototypes - The advanced JavaScript Concepts from you.

Please @HarryBhai, Thoda Jaldi complete playlist upload karo. 😇

[ManKR]

Apka youtube pe lecture hi humare liye gift hai bhaiya...all the best and congratulation for website codeswear❤️✌️✌️✌️✌️

[siddikgaming]

Number is bigger means apko small number enter karna tha 😂

[filmyfuntoosh]

Harry bro dono haath jodke thankyou aapko.... aapke padhaane ka tarika is the best --- these days I am learning python from you(your videos)---
here I made some of the solutions you asked in your old videos--(I am gonna learn the whole of it for sure guru ji)---
Calculator that solves all of the calculations correctly except these--(45*3=555, 56+9=77 and 56/6 = 4 )
it really took more than two hours to me to crack this but all thanks to you


#The Harry Sir's Calculator-

first_number = int(input()) #enter first number you want
demand = input() #select operator you want to select like(+, -, /, *)
second_number = int(input()) #enter second number you want
if first_number ==45 and second_number ==3 and demand == "*":
print("555")
print("answer as per your inputs")
if first_number ==56 and second_number ==9 and demand == "+":
print("77")
print("answer as per your inputs")
if first_number ==56 and second_number ==6 and demand == "/":
print("4")
print("answer as per your inputs")
elif demand =="+":
print(first_number + second_number)
print("answer as per your inputs")
elif demand =="/":
print(first_number / second_number)
print("answer as per your inputs")
elif demand =="*":
print(first_number * second_number)
print("answer as per your inputs")
elif demand =="-":
print(first_number - second_number)
print("answer as per your inputs")

[CoolBoy_Official]

We Appreciate Your Hard Work !
This JavaScript Course is So Helpful
We need Courses about Machine Learning, Android development etc

[teenage_expedition]

Hey Harry bro u know i m 16 and i'm trying to learn python through your 11 hour course it's so.. good, i also edit videos, u can keep me as your editor if u want. But, Thanks For the Information And Courses U are giving us free of cost. Thank You So much

U are the best developer ever who is increasing and sharing awareness in the fields of software development.
Can I get a heart..

[hadeedtmgggg]

Life me pehla banda dekha ha go it e high level precious courses free of cost provide karne ke sath sath apne students ko gift bhe provide karta ha love < #harrybhai

[OmJethva]

Thank you sir, For making videos and doing the hardwork for us even our better future.Sir, You are the Real and one of the Best "Guru". Again Thank you..♥️

[KaranKumar-bqgr]

U have a great heart broo... Proud to learn from IIT topper... 🥰🙏

[samuelfrank]

Nice Sir, You made a course for your business. Thanks for that.

[muhammadatique]

Hi Harry,
Thank you for this amazing "the ultimate javaScript course" . I am doing this course and this exercise in march 2023 . This video make javaScript easy to us.

[jayeshbilwal]

Harry bhai, you make a great contant and specially this tutorial are very helpful for me please upload videos regularly and faster

[wajahatalibasharat]

Harry bi you are doing very yakka in this series. We really appreciate you efforts 👌 .

[rajchatterjee]

let inp = Math.floor(Math.random()*100)
let score=100
let user

while(inp!=user){
score=score-1
user=prompt("Enter the number")
user=Number.parseInt(user)
if(user==inp){
console.log("Congratulation you have succesfully guess the number")
console.log(100-score)
}else{
if(inp>0 && inp<20){
console.log("it is between 0 to 20")
}else if(inp>20 && inp<40){
console.log("it is between 20 to 40")
}else if(inp>40 && inp<60){
console.log("it is between 40 to 60")
}else if(inp>60 && inp<80){
console.log("it is between 60 to 80")
}else if(inp>80 && inp<100){
console.log("it is between 80 to 100")
}
}

}

[dibyajitmazumdar]

Amazing Bro..I am loving this series of Javascript.. I wanted to become expert in Javascript, with the help of you, its becoming possible.. Thanks a

[sumitkesarwani]

Harry Bhaiya, Thank You so much for doing so much for your learned a lot from you and looking forward to acquiring the ultimate knowledge of computer science from you..Thank You!

[kimjong-un]

my solution to this :
let count_num = 0;
function NumberGuess() {
if (guess_num < correct_num) {
alert("ITS LESSER ");
guess_num = prompt("Enter a Number again ");

}
else {
alert("ITS GREATER ");
guess_num = prompt("Enter a Number again ");

}
}

let correct_num = Math.floor((Math.random() * 100));
let guess_num = prompt("Enter a Number between 1 to 100 ");
while (guess_num != correct_num) {
NumberGuess();
count_num++;
}

alert(`, You have Entered the Correct Number "${correct_num}" after : `+ ` "${count_num} " `+ "attemps" );

[anonymous__]

source code :
let random = Math.random()*100;
let random_no = Math.trunc(random)
let score = 100;
let guess;
while(guess!=random_no) {
score = score - 1;
let guess = prompt("Guess the number: ");

if(random_no==guess) {
console.log("You guessed it right and your score is ", score)
console.log("Your Total attemps is :")
console.log(`${100-score}`)
break;
}
else if(random_no>guess){
console.log("Try Bigger Number")
}
else if(random_no<guess && guess<100){
console.log("Try Small Number")
}
}
#HarryBhai #JavaScriptOP