Find the characteristic polynomial of a matrix

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This tutorial goes over how to find the characteristic polynomial of a matrix. The example in this video is a 3x3 matrix, but finding the determinant of (A-λI) will work for a square matrix of any size. It is part of a full free course on linear algebra.

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Thanks for watching, I hope it helps!
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when you were taking the 2 columns to the side, why did you use 30 instead of 3?

woooogl
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it's amazing how you can explain this so well under 4 min while i don't get nothing out of 1 hour of my professor's online class

andresblant
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Thank you, you just saved my life and my exam that will start in 3 hours!

lLl-flrv
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Very informative simplified video. Thank you ❤️

kagisotaukobong
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so useful and brief. Amazing video! A handy shortcut to understand what is written in those frustrating linear algebra books. Thank You So much!

faridabubakr
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can we use it for 4x4 matrix?
Please explain

ansatahira
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Shortcut: char eqn of 3*3 matrix:
£^3 - tr (A) £^2 + (sum of minors along principal diagonal)£ - det(A) = 0
Tr(A) = 2+4+30=36
Minor sum = 0+60+8= 68
Det(A)= 0

£^3 - 36 £^2 + 68 £ = 0

nm
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Thank you so much for the awesome video. Very easy to understand and you went above and beyond and explained so much more which really helped :) subscribed!

sami-iami
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Thank you sir... Iam shocked about the calculations of determinant... Simple trick ... Solved in few seconds...
Woh Sir... 🔥🔥👌👌😍

malikboss
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This is an awesome explanation thank you.

ohmythisisstrong
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Thank you for sharing this _great_ mathematical *LIFE HACK* !!

trendytrenessh
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will the answe be the same if we did determinant of (Labda I - A) instead of (A- Lambda I)?

sarahkamal
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thank you you better than my professor

gyuminoh
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Will the characteristic polynomial ever have a constant in it? Im running into the issue of finding the eigenvalues through factoring with a constant hanging out at the end :')

astranna
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what's the approach for simplifying a polynomial when we have a constant in the equation?

JB-cvyy
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You could've easily expanded the deteminant from first column. There are 2 zeroes in it. That'd me quicker n simpler.

AA-xkkx
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These things are a massive pain. The problems I have encountered so far don't really have any zeroes so I have to row reduce which causes a lot more lamda's to be distributed in the matrix ._.

TheJProductins
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for a 5*5 do we also get 2 colums, is it the same? cos It won't work with one I am trying

pablobiedma
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Sir Kindly continue the Dynamics course again?

irfan_antennas
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When You got to the final step and meant to simplify to get the answer I got confused fr

yusufmuhammed