Problem 4.15 Fundamental of Electric Circuits (Alexander/Sadiku) 5th Ed - Superposition

preview_player
Показать описание
For the circuit in Fig. 4.83, use superposition to find I. Calculate the power delivered to the 3 ohm resistor

Playlists:

  1. Ardi Satriawan
  2. Nodal Analysis
  3. KCL
  4. Kirchhoff Current Law
  5. Electric Circuits
  6. Alexander
Рекомендации по теме
Problem 4.15 Fundamental 0:12:10

Problem 4.15 Fundamental of Electric Circuits (Alexander/Sadiku) 5th Ed - Superposition

Superposition Theorem | 0:14:46

Superposition Theorem | Electric Circuits | Problem 4.15

Problem 3.15 - 0:10:01

Problem 3.15 - Fundamental of Electric Circuits (Sadiku 2020) 7th Ed - Nodal Analysis

Problem 4.20 Fundamental 0:06:08

Problem 4.20 Fundamental of Electric Circuits (Alexander/Sadiku) 5th Ed - Source Transformation

Problem 3.15 Fundamental 0:15:56

Problem 3.15 Fundamental of Electric Circuits (Alexander/Sadiku) 5th Edition

Problem 4.5 Fundamental 0:07:43

Problem 4.5 Fundamental of Electric Circuits (Alexander/Sadiku) 5th Edition - Linearity Property

Source Transformation | 0:06:19

Source Transformation | Electric Circuits | Problem 4.30

Norton Equivalent #448 0:08:39

Norton Equivalent #448

Source Transformation | 0:05:18

Source Transformation | Electric Circuits | Problem 4.24

Source Transformation | 0:05:56

Source Transformation | Electric Circuits | Problem 4.27

Problem 7.42 - 0:09:12

Problem 7.42 - Fundamental of Electric Circuits (Sadiku) - (a) If the switch in Fig. 7.109 has been

Practice Problem 3.4 0:08:32

Practice Problem 3.4 - (2020) Fundamental of Electric Circuits (Sadiku) 7th Ed

Source Transformation | 0:07:57

Source Transformation | Electric Circuits | Practice Problem 4.6

Problem 4.45 Fundamental 0:07:35

Problem 4.45 Fundamental of Electric Circuits (Alexander/Sadiku) 5th Ed - Thevenin Equivalent

Superposition Theorem | 0:15:06

Superposition Theorem | Electric Circuits | Problem 4.16

Practice Problem 4.1 0:04:59

Practice Problem 4.1 - Fundamental of Electric Circuits (Sadiku) 5th Ed [English - Dark Mode]

Problem 3.20 - 0:08:03

Problem 3.20 - Fundamental of Electric Circuits (Sadiku 2020) 7th Ed - Nodal Analysis

Practice Problem 4.1 0:05:13

Practice Problem 4.1 Fundamental of Electric Circuits (Alexander/Sadiku) 5th Edition - Linearity

Problem 2.31 Fundamental 0:06:21

Problem 2.31 Fundamental of Electric Circuits (Alexander - Sadiku)

Basic Electronics For 0:30:15

Basic Electronics For Beginners

Practice Problem 4.13 0:13:17

Practice Problem 4.13 Fundamental of Electric Circuits (Sadiku) 5th Ed Maximum Power Transfer

Thevenin and Norton 0:11:31

Thevenin and Norton Equivalent Circuits #447

PEMDAS Math Problem 0:00:29

PEMDAS Math Problem | Algebra Fundamentals | JusticeTheTutor #math #shorts #maths #mathstricks

Problem 4.51 Fundamental 0:15:17

Problem 4.51 Fundamental of Electric Circuits (Alexander/Sadiku) 5th Ed - Norton Equivalent

Комментарии
Автор

i' = 2, 5 A; i'' = 0.375A; i''' = -1A; --> i = 1, 875A. I performed 3 circuits, each one with only one source ON. I obtained these values. The final answer is in accordance with the book answer.

gusmmattos
Автор

turn of the current source part was mistaken. KVl at i2 answer was wrong. The right answer: (2i2=i1+4 )may be

muntahinaalam
Автор

The question requests you to use the superposition principle. So you should have performed 3 circuits, each one with only 1 source ON, which is the correct method as explained in the very book.

gusmmattos
Автор

a calculation mistake had placed in this math.

jubaerrahman
Автор

you are doing wrong !how can u calculate it two source at a time

mdfahadbinazamrumel
Автор

Sir answer hoba
i = 1.875 A
P = 10.54 w

jakariamridha