Volume Frustum Cone

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Deriving the volume of a frustum of a cone using calculus and the cross-section method of a volume of revolution.
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I was spending so long solving this exact problem, and I said "this is getting really messy, I must be doing something wrong"
Turns out I was on the right track all along, and calculus is just tedious XD
Great explanation, you made this really easy to understand, thank you

equilibrium
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i got this for homework. didnt get this in two hours (I'm a 11th grader don't attack me). watching this video helped a lot. thanks

ChatGPT-gz
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that was a Perfect Video on finding the volume of frustum using Calculus !!! Thank you... YOU are VERY GOOD!! :D ..

ptyptypty
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Thank you for this thorough and clear explanation.

harley
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Your understanding of math is nearly unprecedented. Wow, great video.

T_UwU
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thank you. You help me a lot. Clear that i can understand tho im just 12. But Im rlly into maths!! brilliant video !

XX-hfyg
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Great video thanks Raelene, really clear and succinct explanation of the setup.

stucatz
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Thank you so much Raelene. Best wishes

morjes
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you're so good at explaining it's so easy to understand. looking forward for more tutorials from you!

relgn
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Great method, never thought of using straight line equation, thanks alot

welabird
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Very good derivation. I will return to your Youtube channel for more of your tutorials.

robertvarner
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Im over here just trying to figure out how high I should make the marking on my styrofoam cup with base radus 1" top radius 1.625" and depth 4.3" so i can get exactly 11 in^3 of liquid.

Depressing im an engineer and can't figure this out on my own, but i just ended up finding the equation relating the midpoint radius to the volume and interatively plugged in numbers until I got a solution.

I couldn't find a mesuring cup.

nickt
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Thank you so much, you save the day❤️

eveakristellaurentemunda
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Hi, can I ask on how you can find the height wherein the volume of the frustum is equal? Eg, the total volume is 100 m^3, how can I know the height where I can get 50 m^3? Thank you in advance

jian
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I accidentally wrote y=R for my upper bound, because I misread the h in green as an R. In the problem I had, h and R both had a measurement of 4, so the volume worked out to be the same. However when I looked at the problem later, my bounds didn't make any sense. Glad I caught my mistake.

kenwu
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thanks for the awesome explanation guess I'm just dumb

shaneoclarit
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Did you forget to keep the "h" in the numerator of hR/h?

laurengilmore
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Ok now I know that its better do It ALL for x axis

joaovictorfernandes
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An excellent explanation. Thanks a lot.

ahm
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I thought she would only use geometric formuls...

joseaparicio