Two insulated charged copper spheres A and B have their centers separated by a distance of 50 cm.

Two insulated charged copper spheres A and B have their centers separated by a distance of 50 cm. What is the mutual force of electrostatic repulsion if the charge on each is 6.5 x 107 C? The radii of A and B are negligible compared to the distance of separation. Also compare this force with their mutual gravitational attraction if each weighs 0.5 kg

Solution
Using Coulomb's law,
F= 9×109 "6.5 × 10-7×6.5×10-7" /"(0.50)2"
F= 1.5 × 10 2 N.

The mutual gravitational attraction
Fg= ("6.67 × 10-11×" 0.5 𝑥0.5)/"(0.50)2"
Fg=6.67 × 10-11N
Columbic Force is much greater than gravitational Force

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