The figure shows a closed gaussian surface in the shape of a cube of edge length

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The figure shows a closed Gaussian surface in the shape of a cube of edge length 2.00 m, with one corner at x1 = 5.00 m, y1 = 4.00m. The cube lies in a region where the electric field vector is given by E = -3.00i - 4.00y^2j + 3.00k N/C, with y in meters. What is the net charge contained by the cube?
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Perfect! <3 This was an actual exam question for Physics 1B in UNSW last year xD

laksamanayu
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Shouldn't it be positive 265 for the electric flux because the function of the electric field was once negative and therefore the negatives would cancel out?

maansirathod
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I agree with Maansi Rathod... wouldn't the 265 be positive. Please explain why you did not perform that operation.

raymondbanda
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Hello, I was wondering why do you add the flux on the right and left sides, rather than subtracting?

deeabee
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about the second part on the left side ....why its pos 16?

bigboos
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why we took i and k const shouldn't be the i and j because in Q they said that the cube edge is on x and y!!

asmayahia