Class 12 Ex 1.2 Q9 Math | Relation & Function | Q9 Ex 1.2 Class 12 Math | Ex 1.2 Q9 Class 12 Math

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[vipspark]

Sir your accent makes maths very interesting. We can understanding every concept easy.

[killerguy]

Good 👍🏿 Explanation in short time ⏲ in maath= Nexa Classes.🔥🔥🔥💯💯

[nagaveniv]

Sir bahut easy se aap samjhate all the concepts are very clear sir. Thanu.

[fallenboy]

Sir my teacher said that it is not advisable to write it like this, but I can actually understand your way of writing and teaching more, so if I write like how you write instead of my math teacher, will the board accept it?

[yashdhiman]

Your way impressed me sir and u got a new subscriber ❤️

[segyalgamer]

Bahut acha padata ho sir ap [thank you so much sir❤❤]

[ndvohzh]

Sir is this a surjective function or not?? I know surjective is not needed but plz tell me i have doubt

[rikash]

Sir aap hamare jaise jo tution lene ke liye afford nahi kar sakte unke liye god ho ❤❤🙏🙏

[fabulousfighter]

Fall in love.. With ur teaching style 💜

[SadBoyAditya]

Bhaiya agar aap hindi me padhate to bahut achha rhta har video dekhta fir bhi I like your video ❤❤❤

[stm_motivation]

Thanks a lot sir 🥰🥰you are the best teacher 🔥 I always support you ❤❤❤.. You deserve millions subscribers...❤❤

[rimaborah]

Love from ASSAM❤❤❤Thak you so much sir..

[coolgamer]

Sir fir bhi agar justify kar dete toh hamaare liye concept or clear ho jaata

[DollsiSen]

Sir esa hi koi physics chemistry bhi padha de to acha hoga

[ITSADRGAMER]

Sir ye question ko f(×)=f(y), x=y one-one function AUR
f(×)=y onto function ke methods se kar sakte h.
Ya itna karne par hi full marks mill jayega.(u.p board me)
Sir plz reply me

[bhartijangid]

Sir can we use arrow diagram in exam to show the relation

[AnkitaDutta-ednt]

Sir board m example se prove karenge toh marks ayega n ?

[bhaviknayyar]

Sir if we do not justify our second part till then marks will not be provided.

[mrhkhacker]

Sir ase question direct solve kare ne per number to nahi kate ge

[harshyadav]

Sir, , what if we want to check whether it is onto?